Config Museum: More EIGRP – Answers

By certskills March 26, 2014 09:40

This latest #CCNA config museum  post varied the rules a little, hoping to force you to configure EIGRP to match only one interface at a time with the EIGRP network command. Today’s post gives a little background, and shows the answer.  The config is below the line.


The one possibly-tricky requirement in this case is that R2 and R3 cannot form a neighbor relationship. In fact, you are not allowed to enabled EIGRP on the R2-R3 serial link. The challenge comes in that all three routers use IP addresses in class B network only, so the network command would enable EIGRP on all of a router’s interfaces, which is not allowed on R2 and R3.

For this lab, you need to use the EIGRP network command’s wildcard mask parameter, which then lets you match each interface separately. The matching logic works like an ACL wildcard mask – for instance, the command network on R2 would tell R2 to look for interfaces whose first three octets are 172.18.23, ignoring the 4th octet.

Here’s a brief reminder of the topology, and the list of IP addresses, which will be important for the R2 and R3 configuration:

Figure 1: Router Triangle with IPv4 Subnets

Table 1: IPv4 Addresses

Location IP/mask
R1 F0/0 /26
R1 S0/0/0 /26
R1 S0/0/1 /26
R2 F0/0 /26
R2 S0/0/0 /26
R2 S0/0/1 /26
R3 F0/0 /26
R3 S0/0/0 /26
R3 S0/0/1 /26


First, on R1, a simple network command can be used, without a wildcard mask, because R1 needs to enable EIGRP on all three routers. Example 1 shows the configuration.

Example 1: R1 EIGRP Configuration

R2 needs a network command to match IP addresses (F0/0) and (S0/0/1), but neither of those network commands should match R2’s S0/0/0 IP address of There are many literally correct answers, but if you match the exact address using the wildcard mask of, the result is completely unambiguous. Example 2 shows network commands with that wildcard mask.

Example 2: R2 EIGRP Configuration

R3 has a similar need: to match addresses (F0/0) and (S0/0/0) with network commands, and to not match address (S0/0/1). Just to show a different way to attack the problem, Example 3 uses a wildcard mask of This wildcard mask is the inverse of the subnet mask (, found by subtracting the subnet mask from By using the subnet ID and wildcard mask, the logic matches all addresses in the respective subnet.

Example 3: R3 EIGRP Configuration


Config Museum: More EIGRP
CCNA Question: ARP, Inverse ARP, EIGRP
By certskills March 26, 2014 09:40
Write a comment

No Comments

No Comments Yet!

Let me tell You a sad story ! There are no comments yet, but You can be first one to comment this article.

Write a comment
View comments

Write a comment

Comment; Identify w/ Social Media or Email


Subscribe to our mailing list and get interesting stuff and updates to your email inbox.

Thank you for subscribing.

Something went wrong.